Added spreadsheet style

This commit is contained in:
Crista Lopes
2013-10-21 17:07:36 -07:00
parent 1ae2f4e1c0
commit 5cde2691ea
2 changed files with 54 additions and 0 deletions

16
26-spreadsheet/README.md Normal file
View File

@@ -0,0 +1,16 @@
Style #26
==============================
Constraints:
- The problem is modeled like a spreadsheet, with columns of data and formulas
- Some data depends on other data according to formulas. When data
changes, the dependent data also changes automatically.
Possible names:
- Spreadsheet
- Dataflow
- Active data

38
26-spreadsheet/tf-26.py Normal file
View File

@@ -0,0 +1,38 @@
import sys, re, itertools, operator
#
# The columns. Each column comprises of a data element and a formula.
# The first 2 columns are the input data, so no formulas.
#
all_words = [(), None]
stop_words = [(), None]
non_stop_words = [(), lambda w : w if w not in stop_words[0] else '']
unique_words = [(), lambda word_list: set([w for w in word_list if w != ''])]
counts = [(), lambda w, word_list : word_list.count(w)]
sorted_data = [(), lambda z : sorted(z, key=operator.itemgetter(1), reverse=True)]
#
# The active procedure over the columns of data.
# Call this everytime the input data changes, or periodically.
#
def update():
global non_stop_words
global unique_words
global counts
global sorted_data
# Apply the formulas to the 4 last columns
non_stop_words[0] = map(non_stop_words[1], all_words[0])
unique_words[0] = unique_words[1](non_stop_words[0])
counts[0] = map(counts[1], unique_words[0], itertools.repeat(non_stop_words[0], len(unique_words[0])))
sorted_data[0] = sorted_data[1](zip(list(unique_words[0]), counts[0]))
#
# Load the fixed data into the first 2 columns
#
all_words[0] = re.findall('[a-z]{2,}', open(sys.argv[1]).read().lower())
stop_words[0] = set(open('../stop_words.txt').read().split(','))
# Update the columns with formulas
update()
# Display
for (w, c) in sorted_data[0][:25]:
print w, '-', c