44 lines
1.3 KiB
Python
Executable File
44 lines
1.3 KiB
Python
Executable File
#!/usr/bin/env python
|
|
import re, sys, operator
|
|
|
|
# Mileage may vary. If this crashes, make it lower
|
|
RECURSION_LIMIT = 9500
|
|
# We add a few more, because, contrary to the name,
|
|
# this doesn't just rule recursion: it rules the depth of the call stack
|
|
sys.setrecursionlimit(RECURSION_LIMIT+10)
|
|
|
|
def count(word_list, stopwords, wordfreqs):
|
|
# What to do with an empty list
|
|
if word_list == []:
|
|
return
|
|
# The inductive case, what to do with a list of words
|
|
else:
|
|
# Process the head word
|
|
word = word_list[0]
|
|
if word not in stopwords:
|
|
if word in word_freqs:
|
|
wordfreqs[word] += 1
|
|
else:
|
|
wordfreqs[word] = 1
|
|
# Process the tail
|
|
count(word_list[1:], stopwords, wordfreqs)
|
|
|
|
def wf_print(wordfreq):
|
|
if wordfreq == []:
|
|
return
|
|
else:
|
|
(w, c) = wordfreq[0]
|
|
print w, '-', c
|
|
wf_print(wordfreq[1:])
|
|
|
|
stop_words = set(open('../stop_words.txt').read().split(','))
|
|
words = re.findall('[a-z]{2,}', open(sys.argv[1]).read().lower())
|
|
word_freqs = {}
|
|
# Theoretically, we would just call count(words, word_freqs)
|
|
# Try doing that and see what happens.
|
|
for i in range(0, len(words), RECURSION_LIMIT):
|
|
count(words[i:i+RECURSION_LIMIT], stop_words, word_freqs)
|
|
|
|
wf_print(sorted(word_freqs.iteritems(), key=operator.itemgetter(1), reverse=True)[:25])
|
|
|