Another renumbering, so that all concurrent styles are bundled together
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18
18-no-commitment/plugins-src/frequencies1.py
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18
18-no-commitment/plugins-src/frequencies1.py
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import operator
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def top25(word_list):
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"""
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Takes a list of words and returns a dictionary associating
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words with frequencies of occurrence
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"""
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if type(word_list) is not list or word_list == []:
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return {}
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word_freqs = {}
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for w in word_list:
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if w in word_freqs:
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word_freqs[w] += 1
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else:
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word_freqs[w] = 1
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return sorted(word_freqs.iteritems(), key=operator.itemgetter(1), reverse=True)[:25]
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